11.4 Confinement of positive ions and electrons with a static electric and magnetic field
Let's see what kind of electromagnet we need for our SEM fusor design.
length: 1 mtr
B = μ0 . N/l . I (see hyperphysics)
N= amount of
I = B . l /(μ0 . N)
N = 1000 -> I = 1 . 1 / (2.10-7 .1000) = 5000 A , vey high..
In www.gmw.com/electromagnets , amonst others, an electromagnet (coil) is sold: B= 0,13 T , DC power = 5,18 kW (140 A, 37 V), water cooling 12 ltr/min, 360 turns. Not exactly what we need, but just to get an idea. Not enough magnetic field, consuming a lot of power and also very expensive .
Electromagnets are usually in the form of
iron core solenoids, see
I think it would be better to place an electromagnet with an inner core, on top of the fusor and under the fusor (or if we turn it 90 º, at the sides).
In the next link a permanent magnet, with
dimensions 11x9x2 cm and a magnetic field (Remanencia Br) of 1.3 T is
sold for about 120 €, see:
A small disk with the characteristics as in fig.1:
Fig.1. The magnetic field of a small neodymium magnet
If our SEM fusor had a diameter of 20 cm and a length of 0,5 m, the
circumference would be 62 cm.
I think the best idea is to contruct a vacuum chamber with our experiment and to look for an existing magnet in, for example, an university or company. (universidad de Zaragoza?)
Or perhaps here?